Answer:
B. 17.1
Step-by-step explanation:
Edge 2020. Hope this helps.
The magnitude of 2(u-v +w) is √292.
The given vectors are u = 2i + 3j, v=-i, and w = 5i – 6j.
We need to find the value of 2(u-v+w).
The formula to determine the magnitude of a vector (in two-dimensional space) v = (x, y) is: |v| =√(x²+ y²). This formula is derived from the Pythagorean theorem.
Now, 2(2i + 3j-(-i)+5i-6j)
=2(2i+3j+i+5i-6j)
=2(8i-3j)=16i-6j
The magnitude of 16i-6j=√16²+6²=√256+36=√292
Therefore, the magnitude of 2(u-v +w) is √292.
To learn more about the magnitude of vectors visit:
https://brainly.com/question/24256726.
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