Answer:
220.8L
Explanation:
Given parameters:
Initial volume = 50L
Initial temperature = 15°C = 288K
Initial pressure = 640mmHg
Final temperature = 45°C = 318K
Final pressure = 160mmHg
Unknown:
Final volume = ?
Solution:
Using the combined law;
[tex]\frac{p_{1}v_{1} }{T_{1} }[/tex] = [tex]\frac{p_{2}v_{2} }{T_{2} }[/tex]
p,v and T are pressure, volume and Temperature
[tex]\frac{640 x 50}{288}[/tex] = [tex]\frac{160 x v_{2} }{318}[/tex]
160 x 288 x v₂ = 640 x 50 x 318
v₂ = 220.8L
