Answer:
1. y-intercept = -7
equation: y = 5x - 7
2. y-intercept = -3
equation: y = -2x - 3
3. slope = [tex]\frac{8}{3}[/tex]
Step-by-step explanation:
slope-intercept form: y = mx + b
slope formula: [tex]\frac{y2 - y1}{x2 - x1}[/tex]
To write an equation in slope-intercept form, you need to know the slope(m) and the y-intercept(b).
1. Given: m = 5, P(2, 3). To find the y-intercept, input the given values of m and the point into the equation format and solve for b:
y = mx + b
3 = 5(2) + b
3 = 10 + b
-7 = b
The y-intercept is -7.
Now that we know the slope and the y-intercept, we can write the equation:
y = 5x - 7
2. Given: m = -2, P(-4, 5). To find the y-intercept, input the given values of m and the point into the equation and solve for b:
y = mx + b
5 = -2(-4) + b
5 = 8 + b
-3 = b
The y-intercept is -3.
Now that we know the slope and the y-intercept, we can write the equation:
y = -2x - 3
3. Given: P(3, -5), Q(6, 3). To find the slope, input the given points into the slope formula:
(3, -5) = (x1, y1)
(6, 3) = (x2, y2)
[tex]\frac{y2-y1}{x2-x1}[/tex]
[tex]\frac{3-(-5)}{6-3}[/tex]
Simplify:
3 - (-5) = 3 + 5 = 8
6 - 3 = 3
[tex]\frac{8}{3}[/tex]
The slope of the line passing through points P and Q is [tex]\frac{8}{3}[/tex].
I hope this helps. :)
