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The equation for the reaction of magnesium ribbon and hydrochloric acid is
Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)
If 1.53 g magnesium reacted, how many moles of hydrogen gas was produced?
Report your answer to three significant figures.
Mg = 24.3 g/mol

Respuesta :

Answer: .063

Explanation:

1.53g Mg * (1 mol Mg/ 24.3 g Mg) * (1 mol H2/1 mol Mg) = .063 mol H2

Oseni

The mole of hydrogen gas that will be produced from the reaction would be 0.0630 moles.

From the equation of the reaction:

[tex]Mg(s) + 2 HCl(aq) ---> MgCl_2(aq) + H_2(g)[/tex]

The mole ratio of Mg to H2 gas is 1:1. Thus, for every one mole of Mg consumed by the reaction, 1 mole of H2 is produced, all other things being equal.

Recall that: mole = mass/molar mass

1.53 g of magnesium = 1.53/24.3

                                     = 0.0630 mole (to 3 significant figures)

Since the mole ratio of Mg to H2 is 1:1, it means that the number of moles of hydrogen gas produced would also be 0.0630 moles.

More on calculating moles can be found here: https://brainly.com/question/21085277

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