Answer:
The mid-point of AB is (5,6)
Step-by-step explanation:
The mid-point of two points lies between the middle of two points or divides the line in two equal parts.
The formula for finding mid-point, M, is:
[tex]M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
Here (x1,y1) are the coordinates of first point and (x2,y2) are coordinates of second point.
Given
(2, 3) and (8,9)
Putting the values in the formula
[tex]M(x,y) =(\frac{2+8}{2} , \frac{3+9}{2})\\M = (\frac{10}{2}, \frac{12}{2})\\M = (5,6)[/tex]
Hence,
The mid-point of AB is (5,6)