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Use the equation below to solve the problem that follows.

2H2 (g) + O2 (g) → 2H2O (g)

When David reacts 13.8 grams of hydrogen gas with excess oxygen, 87.0 grams of water are formed. Calculate his percent yield of water.

Respuesta :

Answer: 142.8%

Explanation:

13.8g H2 * (1 mol H2 / 2 g H2) * (2 mol H2O/ 2 mol H2) * (18 g H2O/1 mol H2O) = 124.2 g H2O

we just calculated our theoretical amount that should be formed and we are given the actual

percent yield: actual/theo * 100% = 124.2/87 * 100% = 142.8%

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