Answer:
[tex]P(F/E) = 0.6[/tex]
Step-by-step explanation:
If we are given two dependent events [tex]A[/tex] and [tex]B[/tex] such that their chances of occurrence or the probabilities of the events are: [tex]P(A)[/tex] and [tex]P(B)[/tex].
Then the conditional probability that the event [tex]B[/tex] will occur given that [tex]A[/tex] has already occurred is given by the following formula:
[tex]P(B/A) = \dfrac{P(A \cap B)}{P(A)}[/tex]
Here the two events given are [tex]E[/tex] and [tex]F[/tex].
[tex]P(E\ and\ F)\ or\ P(E\cup F) = 0.3[/tex]
and [tex]P(E) = 0.5[/tex]
As per the above formula that we have already discussed, the formula can be written as:
[tex]P(F/E) = \dfrac{P(E \cap F)}{P(E)}\\\Rightarrow P(F/E) = \dfrac{0.3}{0.5}\\\Rightarrow P(F/E) = \dfrac{3}{5}\\\Rightarrow \bold{P(F/E) = 0.6}[/tex]
