Answer:
129.4g
Explanation:
Reaction equation":
4Al + 3O₂ → 2Al₂O₃
Given mass of oxygen = 115g
Unknown:
mass of aluminum metal that reacted;'
Solution:
We need to convert the given mass of O₂ to mole;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of O₂ = 2(16) = 32g/mol
Number of moles = [tex]\frac{115}{32}[/tex] = 3.6mol
From the balanced reaction equation:
3 moles of O₂ reacted with 4 mole of Al
3.6 moles of O₂ will react with [tex]\frac{3.6 x 4}{3}[/tex] = 4.8mol
Mass of Al = number of moles x molar mass
Mass of Al = 4.8 x 27 = 129.4g
