Answer:
v₂ = 39L
Explanation:
Given parameters:
Initial volume of gas = 20L
Initial temperature = 140K
Unknown:
Final volume = ?
Solution:
Since the standard temperature of any gas is 273K, the final temperature is this 273K;
Applying Charles's law:
[tex]\frac{v_{1} }{T_{1} }[/tex] = [tex]\frac{v_{2} }{T_{2} }[/tex]
v and T are volume and Temperature
[tex]\frac{20}{140}[/tex] = [tex]\frac{v_{2} }{273}[/tex]
v₂ x 140 = 20 x 273
v₂ = 39L
