18. In the figure, o is the center of the circle passing through P, Q, R and S. If angle SOQ = 150°, find the values of x and y.

Answer:
x = 75°
y = 105°
Step-by-step explanation:
Angle subtended on the circumference of the circle is half of the angle subtended on the center of the circle.
[tex] \therefore m\angle SRQ = \frac{1}{2} \times m\angle SOQ\\\\
\therefore x = \frac{1}{2} \times 150\degree \\\\
\red{\bold{\therefore x =75\degree}} \\[/tex]
Quadrilateral PQRS is a cyclic quadrilateral.
[tex] \therefore m\angle R + m\angle P= 180\degree \\\\
\therefore x + y = 180\degree \\\\
\therefore 75\degree + y = 180\degree \\\\
\therefore y = 180\degree - 75\degree \\\\
\purple {\bold {\therefore y = 105\degree}} \\[/tex]