Answer:
The surface area of the cuboid is 378 [tex]\frac{1}{4}[/tex] square inches.
Step-by-step explanation:
A cuboid is a shape which has six surfaces formed from a rectangle. The surface area of a cuboid is the sum of all its individual ares of each surface.
Given the following dimensions of the cuboid:
length = 10 3/4 in = [tex]\frac{43}{4}[/tex] in
width = 8 in
height = 5 1/2 in = [tex]\frac{11}{2}[/tex] in
Since the opposite surface of a cuboid are the same, then;
Area of the 1st surface = length x width
= [tex]\frac{43}{4}[/tex] x 8
= 86 square inches
Area of the 2nd surface = width x height
= 8 x [tex]\frac{11}{2}[/tex]
= 44 square inches
Area of the 3rd surface = length x height
= [tex]\frac{43}{4}[/tex] x [tex]\frac{11}{2}[/tex]
= [tex]\frac{473}{8}[/tex]
= 59 [tex]\frac{1}{8}[/tex] square inches
Surface area of the cuboid = 2 x 86 + 2 x 44 + 2 x [tex]\frac{473}{8}[/tex]
= 172 + 88 + 118.25
= 378.25
Surface area of the cuboid = 378 [tex]\frac{1}{4}[/tex] square inches
