Answer:
Option 2
Step-by-step explanation:
Number of breakdowns of the photocopiers in year 2011,
A1 = 15
A2 = 21
B1 = 34
B2 = 32
B3 = 23
Option (1)
A1 had just under a half the number of breakdowns compared to photocopier B3.
Half of B3 = 12
And A1 = 15
Therefore, A1 > B3
So the statement is False.
Option (2)
A1 had just under 50% of the breakdowns compared to photocopier B2
50% of the breakdowns of B2 = 16
A1 = 15
So, A1 < 50% of B2
Statement (2) is True.
Option (3)
A1 had more than 25 extra breakdowns compared to B1.
A1= 15
B1 = 34
A1 < B1
Therefore, statement is False.
Option (4)
A1 had 6% less breakdowns than photocopier A2.
A1 = 15
A2 = 21
A2 - A1 = 21 - 15 = 6
Percentage less breakdowns = [tex]\frac{6}{21}\times 100[/tex] = 28.6%
So this Option is False.
Therefore, Option (2) is the correct option.
