Answer:
T = 35' 08"
Explanation:
- By definition, the power is the rate of change of energy, with respect to time:
[tex]P = \frac{\Delta E}{\Delta t} (1)[/tex]
- ΔE, in this case, must be equal to the change in the gravitational potential energy during the climb (neglecting friction), as follows:
[tex]\Delta E = m*g*h = 88 kg*9.8m/s2*1100 m = 948640 J (2)[/tex]
- From (1) and (2), being P= 450 W, we can solve for Δt, as follows:
[tex]\Delta t = \frac{\Delta E}{P} = \frac{948640J}{450W} = 2108 sec. (3)[/tex]
- Converting seconds to minutes, we get:
- Δt = 35' 08"
