Answer:
1.039×10^5pa
Explanation:
Pressure due to the weight of a liquid can be expressed as P= ρ g h ,
where p=pressure,
h=depth of the liquid
ρ = density of the liquid
g = acceleration due to gravity.
To calculate the the absolute pressure at the bottom of the container, we use below expresion
P(absolute)= P• [ρ(water) × h(water)× g] + [ ρ(oil) × h(oil)× g]
Where
P•= absolute pressure=101325 Pa
ρ(water= 1000 kg/m³
h(water)= 16.0 cm = 0.16m
ρ(oil)= 0.500= 500kg/m^3
h(oil)= 29.0-cm= 0.29m
If we substitute the values into the above expresion we have
P(absolute)=. 1.01×10^5 + (1000×0.16×9.8) + (500×0.28×9.8)
=1.039×10^5pa
Hence, the absolute pressure at the bottom of the container is 1.039×10^5pa
