Answer:
CH₃COOH + NaOH → NaCH₃COO + H₂O
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻ pKa = 4.75
Explanation:
Acetic acid and NaOH make a neutralization reaction, where a salt and water are formed.
CH₃COOH + NaOH → NaCH₃COO + H₂O
Acetic acid gives protons to medium
NaOH gives hydroxides to medium
When we have protons and hydroxides, we can produce water. That's why it is a neutralization reaction.
The acid is weak, so the formed CH₃COO⁻ becomes in the conjugate strong base. This anion can make hydrolysis to water.
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻ pKa = 4.75
The NaOH is a strong base, so the Na⁺, as the conjugate weak acid, can't make hydrolysis.
We can't make this equilibrium.
Na⁺ + H₂O ⇄ NaOH + H⁺ IMPOSSIBLE
