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The probability that Junkins Food launches a new product in November is 55%. The probability that the director of new products plans a vacation in November is 8.3%. If these events are independent, what is the probability that the director of new products is on vacation when a new product launches in November?

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MrRoyal

Answer:

[tex]Probability = 0.04565[/tex]

Step-by-step explanation:

Given

Represent the event that the new product launched in November with N

Represent the event that the director plans a vacation in November with V

Such that

[tex]P(N) = 55\%[/tex]

[tex]P(V) = 8.3\%[/tex]

Since N and V are independent events.

The required probability is calculated as follows;

[tex]Probability = P(N) * P(V)[/tex]

[tex]Probability = 55\% * 8.3\%[/tex]

Convert to decimals

[tex]Probability = 0.55 * 0.083[/tex]

[tex]Probability = 0.04565[/tex]

Hence, the required probability is 0.04565

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