Answer:
[tex]A=19.4g[/tex]
Explanation:
Hello!
In this case, since the radioactive decay is modelled by using the following equation:
[tex]A=A_0*2^{\frac{-t}{t_{1/2}} }[/tex]
Thus, since A is referred to the initial and final amounts the radioactive isotope, we can compute the remaining mass of P32 once 4.00 days have passed by plugging in the given data:
[tex]A=23.5g*2^{\frac{-4.00days}{14.3days} }\\\\A=19.4g[/tex]
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