Answer:
[tex]Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)[/tex]
Explanation:
Hello!
In this case, since writing the net ionic equation implies the complete molecular equation, we should start by:
[tex]Zn(s)+2HBr(aq)\rightarrow ZnBr_2(aq)+H_2(g)[/tex]
Next, we represent the ionization of the aqueous species:
[tex]Zn(s)+2H^+(aq)+2Br^-(aq)\rightarrow Zn^{2+}(aq)+2Br^-(aq)+H_2(g)[/tex]
Whereas the spectator ions, those at both reactants and products are cancelled out so the net ionic equation is obtained:
[tex]Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)[/tex]
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