How many total molecules will be present when the reaction of 5,000 molecules of CS2 with 15,000 molecules of 0 2 goes to completion?
CS2(1)+3 02(g) CO2(g) + 2S02(g)
(A) 5,000
(B) 10,000
(C) 15,000
(D) 20,000

Respuesta :

Answer:

  (C)  15,000

Explanation:

The equation is ...

  CS₂ +3O₂ ⇒ CO₂ +2SO₂

This indicates 1 molecule of CS₂ combines with 3 molecules of O₂ to produce 1 molecule of CO₂ and 2 molecules of SO₂.

Counting molecules, we see that the original 4 molecules in a 1:3 ratio become 1+2 = 3 molecules. The reactants present are in the necessary 1:3 ratio of CS₂ : O₂, so there are no limitations on the reaction. It can use all of the original molecules to produce ...

  (3/4)(20,000) = 15,000

molecules of product.

When the reaction completes, there will be 15,000 molecules present.