Answer:
249 K
Explanation:
Step 1: Given data
- Mass of nitrogen (m): 4.03 g
- Volume of the gas (V): 921 mL = 0.921 L
- Pressure of the gas (P): 3.19 atm
Step 2: Calculate the moles corresponding to 4.03 g of nitrogen
The molar mass of N₂ is 28.01 g/mol.
4.03 g × 1 mol/28.01 g = 0.144 mol
Step 3: Calculate the temperature of the gas sample
We will use the ideal gas equation.
P × V = n × R × T
T = P × V / n × R
T = 3.19 atm × 0.921 L / 0.144 mol × 0.0821 atm.L/mol.K
T = 249 K
