Answer:
The answer is below
Explanation:
It have been shown that domestic turkeys require about 13.6 grams of food per pound of body weight each day to sustain weight. A gobbler is a male turkey.
The food consumed by a male turkey that is 17.5 lbs = 13.6 grams of food per pound * 17.5 pound = 238 grams.
7 gobblers = 7 male turkeys, hence:
The food consumed by 7 gobblers = 238 grams * 7 = 1666 grams
