Answer:
[tex]41\ units[/tex]
Step-by-step explanation:
[tex]As\ we\ know\ that,\\The\ sum\ of\ two\ sides\ of\ a\ triangle\ will\ always\ be\ greater\ than\ the\ Third\ Side.\\Hence,\\As\ we\ are\ given,\\Length\ of\ Side\ 1=24\ units\\Length\ of\ Side\ 2=18\ units\\Hence,\\The\ Length\ of\ Side\ 3<(24+18)\\Or,\\The\ Length\ of\ Side\ 3<42\\Now,\\As\ the\ length\ of\ third\ side\ cannot\ be\ equal\ to\ the\ sum\ of\ the\ other\ two sides.\\Hence,\\The\ Length\ of\ Side\ 3\neq 42\\As\ we\ are\ told\ to\ find\ the\ integer\ value,\\[/tex]
[tex]The\ nearest\ integer\ lesser\ than\ 42\ is\ 42-1\ or\ 41.\\Hence,\\The\ largest\ possible\ integer\ length\ of\ the\ third\ side\ of\ the\ triangle=41\ units[/tex]
