Answer:
not sure but 17.714 smthng like that
Explanation:
first find a=62/35 from f=m*a then v=a*t
(62/35)*10
A force of 62 N acting on a 35 kg object applies an acceleration a of
62 N = (35 kg) a
a = (62 N) / (35 kg) ≈ 1.8 m/s²
If v₀ is the object's initial velocity, then after 10.0 s it attains a final velocity v of
v = v₀ + a t
v = v₀ + (1.8 m/s²) (10.0 s)
v = v₀ + 18 m/s
so that the change in velocity is
∆v = v - v₀ = 18 m/s
