Answer:
The value is [tex]k = 0.7239[/tex]
Explanation:
From the question we are told that
The angle between the transmission axes of the polarizer [tex]\theta = 42^o[/tex]
Gnerally the intensity light emerging from the first polarizer is
[tex]I_1 = \frac{I_o }{2}[/tex]
Generally according to malus's law the intensity of light emerging from the second polarizer is mathematically represented as
[tex]I_2 = I_1 * cos^{2} (\theta )[/tex]
=> [tex]I_2 = \frac{I_o }{ 2} * cos^{2} (42 )[/tex]
=> [tex]I_2 = 0.2761 I_o[/tex]
Generally the incident intensity is BLOCKED by the polarizers is mathematically represented as
[tex]I = I_o - I_2[/tex]
=> [tex]I = I_o - 0.2761 I_o[/tex]
=> [tex]I = 0.7239 \ I_o[/tex]
Hence the fraction of the incident intensity is BLOCKED by the polarizers is
[tex]k = 0.7239[/tex]
