P4 (s) + 6Cl2 (g) -> 4 PCL3 (l)
What is the maximum amount of phosphorus trichloride that can be formed if 10 molecules of P 4 are mixed with 36 molecules of chlorine?

Respuesta :

Answer:

24 molecules of phosphorus trichloride can be formed

Explanation:

Based on the equation:

P4(s) + 6Cl2(g) → 4PCl3

1 mole of P4 reacts with 6 moles of Cl2 to produce 4 moles of PCl3.

When 10 molecules of P4 react, 60 molecules of Chlorine are needed. As there are just 36 molecules, Cl2 is limiting reactant.

If 36 molecules of chlorine are added, molecules of PCl3 produced are:

36 molecules Cl2 * (4 PCl3 / 6 Cl2) =

24 molecules of phosphorus trichloride can be formed

Oseni

The maximum amount of phosphorus trichloride that can be formed from 10 molecules of P4 and 36 molecules of chlorine would be 24 molecules.

From the balanced equation of the reaction, the mole ratio of P4 to Cl2 to PCl3 is 1:6:4.

Thus, for every 1 molecule of P4, 6 molecules of Cl2 would be required.

In the same vein, 10 molecules of P4 will require 60 molecules of Cl2. But there are just 36 molecules of Cl2. Thus, Cl2 is a limiting reactant.

The mole ratio of Cl2 to PCl3 is 6:4 or 3:2.

Hence, with 36 molecules of Cl2, the maximum amount of PCl3 that can be formed would be:

             

                   36 x 2/3 = 24 molecules.

More on stoichiometric calculations can be found here: https://brainly.com/question/8062886?referrer=searchResults