A polynomial has been factored, as shown below:
f(x) = (x - 9)(x + 12)(x - 24)
What are the zeros of the polynomial?
1)-9,9, -12, 12, -24, 24
2) -9, 12, -24
3) 9.-12, 24
4) 9, 12, 24

To find the zeros of a polynomial, you make every factored parentheses equal to zero. You basically make the other side equal to zero and solve for x.

So,

[tex]f(x)=(x-9)(x+12)(x-24)\\0=(x-9)(x+12)(x-24)\\x-9=0\\x=9\\x+12=0\\x=-12\\x-24=0\\x=24[/tex]

Your zeros are x = 9, -12, 24

So your answer is 3) 9, -12, 24

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A polynomial has been factored, as shown below: f(x) = (x - 9)(x + 12)(x - 24) What are the zeros of the polynomial? 1)-9,9, -12, 12, -24, 24 2) -9, 12, -24 3) 9.-12, 24 4) 9, 12, 24

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A polynomial has been factored, as shown below:
f(x) = (x - 9)(x + 12)(x - 24)
What are the zeros of the polynomial?
1)-9,9, -12, 12, -24, 24
2) -9, 12, -24
3) 9.-12, 24
4) 9, 12, 24