The line equation : y=8x-26
Further explanation
Given
The points (3, -2) and (4, 6)
Required
Line equation
Solution
General formula
y-y1 = m(x-x1)
or
y = mx + c
Where
m = straight-line gradient which is the slope of the line
x1, y1 = the Cartesian coordinate that is crossed by the line
c = constant
The formula for a gradient (m) between 2 points in a line
m = Δy / Δx
Input given values in formula :
(3, -2⇒)x1, y1
(4, 6)⇒x2, y2
[tex]\tt y-(-2)=\dfrac{6-(-2)}{(4-3)}(x-3)\\\\y+2=8(x-3)\\\\y=8x-24-2\\\\y=8x-26[/tex]
