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Suppose a chromium atom in the oxidation state formed a complex with one chloride anion and five water molecules. Write the chemical formula of this complex.

Respuesta :

Answer:

[CrCl(H₂O)₅]²⁺

Explanation:

Oxidation Number of Chromium = +3

Oxidation Number of Chloride = -1

Oxidation Number of Water molecules = 0

Since the complex contains one chloride atom (Cl), 5 water molecules (H₂O) and one chromium atom (Cr). We have;

CrCl(H₂O)₅

The oxidation number of the mixture is given as;

+3   + (-1)  + 5(0) = x

x = + 3 - 1 + 0

x = +2

The chemical formular of the complex is;

[CrCl(H₂O)₅]²⁺

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