b) The sum of the ages of the father and son is 44 years. After 8 years, the age of
father will be twice the age of the son. Find their present ages,​

Respuesta :

Let the present age of father = x years

and the present age of son = y years

according to the first condition

x + y =44 ........(i)

according to the second condition

x+8 = 2(y+8)

or x+ 8 = 2y + 16

or x- 2y = 8 ............(ii)

solve the equation (i) & (ii) we get

x + y =44

x- 2y = 8

••••••••••••••••••••••••

3y = 36

or y = 12

put the value of y in equation (i), we get

x + 12 =44

or x = 32

so the present age of father = x =32 years

and the present age of son = y = 12 years.

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