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Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE =2x, BE = y +10, CE =x+2 and
DE = 4y - 8. Find x.
A. 4
B. 6
C. 2
D. 8

Respuesta :

abidemiokin

Answer:

x = 2

Step-by-step explanation:

Given parallelogram ABCD with diagonals AC and BD intersect at point E, then;

AE = CE and BE = DE

Given;

AE =2x, BE = y +10, CE =x+2 and  DE = 4y - 8.

Recall that AE = CE

2x = x+2

2x - x = 2

x = 2

Hence the value of x is 2

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