Answer:
Period of motion is approximately 0.5447 seconds
Explanation:
We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)
F = k * x
0.012 kg * 9.8 m/s^2 = k 0.034 m
k = 0.012 kg * 9.8 m/s^2 / (0.034 m)
k = 3.46 N/m
now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':
[tex]T=2\pi\,\sqrt{\frac{m}{k} }[/tex]
which in our case becomes:
[tex]T=2\pi\,\sqrt{\frac{0.026}{3.46} } \approx 0.5447\,\,sec[/tex]
