Answer:
376.5 m
Explanation:
we know that
s=ut + 1/2 at^2
so here
u=49 m/s
t=5s
and a=g=9.8 m/s^2
so
s= 49Ă—5 +1/2 Ă—9.8Ă— 5Ă—5
= 254+ 122.5
s= 376.5
Maximum height reached by the ball in 5 seconds is 370 meter.
Given that;
Initial speed of ball = 49 m/s
Total time taken = 5 seconds
Find:
Maximum height reached by the ball in 5 seconds
Computation:
s = ut + (1/2)(g)(t²)
s = (49)(5) + (1/2)(10)(5²)
s = 245 + (5)(25)
s = 245 + 125
s = 370 meter
Height reached = 370 meter
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