A hemispherical tank is filled with water and has a diameter of 17 feet. If water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?

Respuesta :

Answer:

The total weight = 1286 × 62.4 = 80246 pounds.  

Step-by-step explanation:

The formula of the volume of the sphere is

V = 4/3×π×r³

Given

d = 17 feet

as

d = 2r

so

r = d/2 = 17/2 = 8.5 feet

as

V = 4/3×π×r³

Since we need half of the volume as it is a hemispherical tank.

[tex]\frac{V}{2}=\pi r^3[/tex]

    [tex]=\frac{2}{3}\times \:3.14\times \:8.5^3[/tex]

    = 1286 ft³

Given that the weighs 62.4 pounds per cubic foot

Thus,

The total weight = 1286 × 62.4 = 80246 pounds.                

The total weight of the water in a full hemispherical tank, which is filled with water, is 80,260 pounds.

What is the volume of hemisphere?

The volume of the hemisphere is the amount of quantity, which is obtained by it in the 3 dimensional space.

The volume of the hemisphere can be calculated with the following formula.

[tex]V=\dfrac{2}{3}\pir^3[/tex]

Here, {r} is the radius of the hemisphere.

A hemispherical tank is filled with water and has a diameter of 17 feet. The radius of the hemisphere will be half of the diameter. Thus,

[tex]r=\dfrac{17}{2}\\r=8.5\rm\;ft[/tex]

The volume of the hemispherical tank is,

[tex]V=\dfrac{2}{3}\pi(8.5)^3\\V=1286.22\rm\; ft^3[/tex]

The water weighs 62.4 pounds per cubic foot. Thus, the total weight of the water in a full tank is,

[tex]W={1286.22}\times62.4\\W=80260\rm \;pounds[/tex]

Hence, the total weight of the water in a full hemispherical tank, which is filled with water, is 80,260 pounds.

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