Answer:
y = [tex]\frac{11}{6}x+\frac{53}{2}[/tex]
Step-by-step explanation:
Let the equation of the line passing through a point (x', y') and slope 'm' is,
y - y' = m(x - x')
Slope of the line passing through [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is represented by,
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
If two points given in the bale are (-9, 10) and (3, 32),
Slope 'm' = [tex]\frac{32-10}{3-(-9)}[/tex]
= [tex]\frac{22}{12}[/tex]
= [tex]\frac{11}{6}[/tex]
Therefore, equation of the line passing through (3, 32) and slope = [tex]\frac{11}{6}[/tex] will be,
y - 32 = [tex]\frac{11}{6}(x - 3)[/tex]
y = [tex]\frac{11}{6}x-\frac{11}{2}+32[/tex]
y = [tex]\frac{11}{6}x+\frac{53}{2}[/tex]
