An object located near the surface of Earth has a weight of a 245 N
object?
• What is the mass of the object?
• What is the weight of the object on Mars where the gravity is
3.72 m/s?

Respuesta :

Answer:

The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.

Explanation:

Weight of the object on the surface of Earth, W = 245 N

On the surface of Earth, acceleration due to gravity, g = 10 m/s²

Weight of an object is given by :

W = mg

m is mass

[tex]m=\dfrac{W}{g}\\\\m=\dfrac{245\ N}{10\ m/s^2}\\\\=24.5\ kg[/tex]

So, the mass of the object is 24.5 kg

Acceleration due to gravity on Mars, g' = 3.72 m/s²

Weight of the object on Mars,

W' =mg'

W' = 24.5 kg × 3.72 m/s²

= 91.14 N

So, the weight of the object on Mars is 91.14 N.

  • Mass of the object located near the Earth surface is 25kg
  • The weight of the object on Mars with the given gravity is 93 Newtons.

Given the data in the question;

Weight of object; [tex]W = 245N[/tex]

  • What is the mass of the object.

Weight the measure of the force of gravity pulling down on a particle or object.

It is expressed as:

[tex]W = m* g[/tex]

Where m is mass of the object and g is acceleration due to gravity { Acceleration due gravity of Earth [tex]g_{earth} = 9.8m/s^2[/tex] }

We substitute our values into the equation

[tex]245N = m * 9.8m/s^2\\\\245kg.m/s^2 = m * 9.8m/s^2\\\\m = \frac{245kg.m/s^2}{9.8m/s^2} \\\\m = 25kg[/tex]

Therefore, mass of the object located near the Earth surface is 25kg

  • Weight of the object on Mars where the gravity [tex]3.72m/s^2[/tex]

So on planet Mars; [tex]g = 3.72m/s^2[/tex], we know that mass of the object is [tex]25kg[/tex]

We substitute into our equation

[tex]W = m* g[/tex]

[tex]W = 25kg * 3.72m/s^2\\\\W = 93kg.m/s^2\\\\W = 93N[/tex]

Therefore, the weight of the object on Mars with the given gravity is 93 Newtons.

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