Answer:
|Z| = |-4.089| > 1.645 at 0.10 level of significance
Null hypothesis is rejected at 0.10 level of significance
There is a difference between the two Population proportions
Step-by-step explanation:
Step(i):-
Given first sample size (n₁) = 50
Given proportion of the first sample p⁻₁= 0.2
Given second sample size (n₂) = 50
Given proportion of the second sample p₂⁻ = 30/50 = 0.6
Null Hypothesis : H₀: p₁⁻=p₂⁻
Alternative Hypothesis : H₁: p₁⁻≠p₂⁻
Step(ii):-
Z-statistic
[tex]Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} } +\frac{1}{n_{2}) } } }[/tex]
Where
[tex]P = \frac{n_{1}p_{1} +n_{2} p_{2} }{n_{1} +n_{2} }[/tex]
[tex]P = \frac{50X0.2+50X0.6}{50+50} = 0.4[/tex]
Z-statistic
[tex]Z = \frac{0.2-0.6}{\sqrt{0.4 X 0.6(\frac{1}{50}+\frac{1}{50} } }[/tex]
Z = -4.089
Level of significance =0.10
Z₀.₁₀ = 1.645
|Z| = |-4.089| > 1.645 at 0.10 level of significance
Null hypothesis is rejected at 0.10 level of significance
Final answer:-
There is a difference between the two Population proportions