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The Chapin Social Insight Test evaluates how accurately the subject appraises other people socially. In the reference population used to develop the test, scores are approximately normally distributed with mean 25 and standard deviation 5. The range of possible scores is 0 to 41. a) What proportion of subjects in the population will have scores above 31

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Answer:

0.11507

Step-by-step explanation:

Given that:

Mean (m) = 25

Standard deviation = 5

Proportion of subject in the population with score above 31

P(x > 31)

Obtain the standardized score of x = 31

Zscore = (x - m) / s

Zscore = (31 - 25) / 5

Zscore = 6 / 5

Zscore = 1.2

Hence, p(Z > 1.2)

Using the Z probability calculator :

p(Z > 1.2) = 0.11507