Respuesta :

absor201

Answer:

An equation in​ point-slope form of the line that passes through the given point and with the given slope m = 4 will be:

[tex]y-1 = 4(x-(-4))[/tex]

Step-by-step explanation:

Given

  • The point = (-4, 1)
  • m = 4

Using the point-slope form of the line equation

[tex]y-y_1=m\left(x-x_1\right)[/tex]

here:

  • m = slope
  • (x₁, y₁) = point

substituting the values m = 4 and the point (-4, 1) in the point-slope form of the line equation

[tex]y-y_1=m\left(x-x_1\right)[/tex]

[tex]y-1 = 4(x-(-4))[/tex]

Thus,

An equation in​ point-slope form of the line that passes through the given point and with the given slope m = 4 will be:

[tex]y-1 = 4(x-(-4))[/tex]

Note: It can further be simplified

[tex]y-1=4\left(x+4\right)[/tex]

Add 1 to both sides

[tex]y-1+1=4\left(x+4\right)+1[/tex]

[tex]y=4x+17[/tex]

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