Answer:
Step-by-step explanation:
we know that distance d from the focus to P should be the same to the distance from P to the directrix
(x-h)^2=4p(y-k)
we need to find the y coordinate,
x is the same from focus, 3
y=(3, (4+2)/2)=(3,3)
we find p now by subtracting the y from the focus from the y that we just found
p=4-3=1
again (x-h)^2=4p(y-k), p=1
(x-3)^2=4(1)(y-3)
(x-3)^2=4(y-3), (x-3)^2=4y-12
simplify
4y=(x-3)^2+12
y=((x-3)^2)/4 + 3
The equation for the parabola would be y = ((x-3)^2)/4 + 3.
We already know that distance d from the focus to P must be the same as the distance from P to the directrix
(x-h)^2 = 4p(y-k)
x is the same from focus 3
y = (3, (4+2)/2)
y =(3,3)
by subtracting the y from the focus from the y that we get
p = 4-3 =1
similalry,
(x-h)^2=4p(y-k), p=1
(x-3)^2=4(1)(y-3)
(x-3)^2=4(y-3),
(x-3)^2=4y-12
simplify it;
4y=(x-3)^2+12
y = ((x-3)^2)/4 + 3
Thus, the equation for the parabola would be y = ((x-3)^2)/4 + 3.
Learn more about parabola here;
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