Answer:
2 seconds later
Step-by-step explanation:
Since the required equation is lacking, let the equation modeled by the height be expressed as y = -16t² + 64
The ball hits the ground at y =0. Substitute y = 0 into the expression and find t;
Since y = -16t² + 64
0 = -16t² + 64
16t² = 64
t² = 64/16
t² = 4
t = ±√4
t = 2 and -2
Time cannot be negative, hence the ball hits the ground 2 seconds later.
Note that the equation used was assumed. Similar solution can be applied for any given equation.
