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Two copper spheres are currently 1.2 meters apart. One sphere has a charge of +2.2 x 10-4 C and the other has a charge of -8.9 x 10-4C.
What is the force between the charged spheres?
Is the force attractive or repulsive?

Two copper spheres are currently 12 meters apart One sphere has a charge of 22 x 104 C and the other has a charge of 89 x 104C What is the force between the cha class=

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Answer:

The force between the charged spheres is 1,223.75 N

The force is attractive because opposite charges mutually attract.

Explanation:

Coulomb's Law

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Expressing the above as a formula:

[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]

Where:

[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]

q1, q2 = the objects' charge

d= The distance between the objects

The copper spheres have charges of:

[tex]q_1=+2.2\cdot 10^{-4}\ c[/tex]

[tex]q_2=-8.9\cdot 10^{-4}\ c[/tex]

Note the charges have opposite signs.

They are separated by d=1.2 m

Applying Coulomb's formula:

[tex]\displaystyle F=9\cdot 10^9\frac{2.2\cdot 10^{-4}\cdot 8.9\cdot 10^{-4}}{1.2^2}[/tex]

[tex]\displaystyle F=9\cdot 10^9\frac{1.958\cdot 10^{-7}}{1.44}[/tex]

F = 1,223.75 N

The force between the charged spheres is 1,223.75 N

The force is attractive because opposite charges mutually attract.