Answer:
4[tex]\sqrt{2}[/tex] +2
Step-by-step explanation:
[tex]\frac{6-\sqrt{8}}{\sqrt{2}-1}[/tex]
=[tex]\frac{6-\sqrt{8}}{\sqrt{2}-1}[/tex] ×[tex]\frac{\sqrt{2}+1}{\sqrt{2}+1}[/tex]
=[tex]\frac{(6-\sqrt{8})(\sqrt{2}+1)}{2-1}[/tex]
=6[tex]\sqrt{2}[/tex] + 6 -[tex]\sqrt{8}\sqrt{2}[/tex] - [tex]\sqrt{8}[/tex]
=6[tex]\sqrt{2}[/tex] + 6 - 4 - [tex]\sqrt{8}[/tex]
=6[tex]\sqrt{2}[/tex] + 2 - [tex]\sqrt{8}[/tex]
=6[tex]\sqrt{2}[/tex] + 2 - 2
=4[tex]\sqrt{2}[/tex] +2
for [tex]\sqrt{8}[/tex] = 2[tex]\sqrt{2}[/tex] ,
[tex]\sqrt{8}[/tex] = [tex]\sqrt{2*2*2}[/tex]
= ([tex]\sqrt{2}[/tex])^2 × [tex]\sqrt{2}[/tex]
=2 ×[tex]\sqrt{2}[/tex]
