Answer:
(3, 1 )
Step-by-step explanation:
The centre of the circle is at the midpoint of the diameter.
Given endpoint (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )
Here (x₁, y₁ ) = (9, 7) and (x₂, y₂ ) = (- 3, - 5 ) , then
midpoint = ( [tex]\frac{9-3}{2}[/tex], [tex]\frac{7-5}{2}[/tex] ) = ( [tex]\frac{6}{2}[/tex], [tex]\frac{2}{2}[/tex] ) = (3, 1 )
Thus centre of circle = (3, 1 )
