An aerosol can contains 400.0 ml of compressed gas at 5.2 atm pressure. When the gas is sprayed into a large plastic bag, the bag inflates to a a volume of 2.14 L. What is the pressure of gas inside the plastic bag?

The relation between the pressure (P) and volume (V) of a gas is given by the Boyle's law. According to this, the volume is inversely proportional to the pressure:

P₁ x V₁ = P₂ x V₂

From the problem, we have:

V₁= 400.0 mL x 1 L/1000 mL = 0.4 L

P₁= 5.2 atm

V₂= 2.14 L

We calculate the final pressure (P₂) from the equation, as follows:

P₂ = (P₁ x V₁)/V₂ = (5.2 atm x 0.40 L)/ 2.14 L = 0.97 atm ≅ 1 atm

Therefore, as the volume is increased (from 0.4 L to 2.14 L), the pressure in decreased (from 5.2 atm to 0.97 atm).

dsdrajlin dsdrajlin · Answer 2 · 2022-02-04T12:33:03+01:00

A 400.0-mL can contains compressed gas at 5.2 atm. The gas is sprayed into a bag, that inflates to 2.14 L at 0.97 atm.

What does Boyle's law state?

Boyle's law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

A 400.0-mL can contains compressed gas at 5.2 atm. The gas is sprayed into a bag, that inflates to 2.14 L. We can calculate the final pressure of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁ / V₂

P₂ = 5.2 atm × 0.4000 L / 2.14 L = 0.97 atm

where,

P₁ and V₁ are the initial pressure and volume.
P₂ and V₂ are the final pressure and volume.

A 400.0-mL can contains compressed gas at 5.2 atm. The gas is sprayed into a bag, that inflates to 2.14 L at 0.97 atm.

Learn more about Boyle's law here: https://brainly.com/question/469270