Samuel found the difference of the polynomials. (15x^2+11y^2+8x)-(7x^2+5y^2+2x)= blankx^2+6y^2+6x What value is missing from his solution?

Respuesta :

Answer:

Co-efficient of [tex]x^{2}[/tex] is missing.

It should be 8[tex]x^{2}[/tex].

Step-by-step explanation:

Given two polynomials:

1st polynomial: [tex]15x^2+11y^2+8x[/tex]

2nd polynomial: [tex]-7x^2+5y^2+2x[/tex]

To find:

The value in the blank:

[tex](15x^2+11y^2+8x)-(7x^2+5y^2+2x)= \_\_ \ x^2+6y^2+6x[/tex]

Solution:

Here, we have 3 pair of like terms.

2 terms with [tex]x^{2}[/tex], 2 terms with [tex]y^{2}[/tex]and 2 terms with [tex]x[/tex].

Like terms can be subtracted.

Subtracting the terms with [tex]y^{2}[/tex], the coefficients will get subtracted.

[tex]11y^2 - 5y^2 = 6y^2[/tex]

Subtracting the terms with [tex]x[/tex], the coefficients will get subtracted.

[tex]8x -2x=6x[/tex]

Subtracting the terms with [tex]x^{2}[/tex], the coefficients will get subtracted.

[tex]15x^2 - 7x^2 =\bold{8}x^2[/tex]

Therefore, the answer is:

Co-efficient of [tex]x^{2}[/tex] is missing.

It should be 8[tex]x^{2}[/tex].