Complete Question
A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.How much force does she use to pull on the rope
Answer:
The value is [tex]F = 150 \ N[/tex]
Explanation:
From the question we are told that
The mass of the man is [tex]m_m = 75 \ kg[/tex]
The mass of the woman is [tex]m_f = 100 \ kg[/tex]
The acceleration of the man is [tex]a_m = 2.0 \ m/s ^2[/tex]
Generally the force which she used to pull the rope is mathematically represented as
[tex]F = m * a[/tex]
=> [tex]F = 75 * 2[/tex]
=> [tex]F = 150 \ N[/tex]
