Answer:
[tex]\dfrac{1}{2}[/tex]
Step-by-step explanation:
Given that:
10 number of blocks which have numbers from 1 through 10.
To find:
Probability of randomly choosing a block that has an even number.
Solution:
The given set of numbers is: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
There are a total of 5 Even numbers are {2, 4, 6, 8, 10}.
And There are a total of 5 Odd number are {1, 3, 5, 7, 9}.
Formula for probability of an event E can be observed as:
[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}[/tex]
Here, Event E is randomly choosing an even number.
Number of favorable cases = 5
Total number of cases = 10
Therefore, the required probability is:
[tex]P(E) = \dfrac{5}{10}\\\Rightarrow P(E) = \dfrac{1}{2}[/tex]
