The value of theta is pi/4
[tex]\arccos \left(\frac{\sqrt{2}}{2}\right)= \theta[/tex]
here the value of the,
The value of the arccos(sqrt2/2) is,
[tex]\arccos \left(\frac{\sqrt{2}}{2}\right)=\frac{\pi }{4}[/tex]
Therefore the value of theta is pi/4
So the second option is correct.
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