Answer:
Step-by-step explanation:
The null and the alternative hypothesis are:
[tex]\mathbf{ H_o: \rho = 0} \\ \\ \mathbf{H_1: \rho \ne 0}[/tex]
The test statistics is as follows:
[tex]t = \dfrac{r\sqrt{n-2} }{\sqrt{1-r^2}}[/tex]
[tex]t = \dfrac{0.4 \sqrt{30-2} }{\sqrt{1-0.4^2}}[/tex]
[tex]t = \dfrac{0.4 \sqrt{28} }{\sqrt{0.84}}[/tex]
t = 2.3094
The critical value
[tex]t_{\alpha/df} = t_\ \{0.05/2 \ , \ 30-2 \} } \\ \\ = t_{0.025,28} = \pm 2.048 ( from \ the \ t-tables)[/tex]
Decision rule:
To reject [tex]H_o[/tex] if t > [tex]t_{\alpha/df}[/tex].
So since t > [tex]t_{\alpha/df}[/tex]. we reject [tex]H_o[/tex] at ∝ = 0.05
Conclusion: There is sufficient evidence to conclude that blood pressure and patient calcium are linearly related.
