Answer:
NH4NO2.
Explanation:
Hello!
In this case, since the by-mass percent of any element (in this case nitrogen) is computed by:
[tex]\%N=\frac{n_N*m_N}{M}*100\%[/tex]
Whereas n is the number of N in the compound, m the atomic mass of nitrogen (14.01 g/mol) and M the molar mass of the compound. Thus, down below we can find the molar mass of each compound and the by-mass percent of nitrogen:
NH4NH2CO2 = 78.07 g/mol
[tex]\%N=\frac{2*14.01}{78.07}*100\%=35.9\%[/tex]
NH4NO2 = 64.06 g/mol
[tex]\%N=\frac{2*14.01}{64.06}*100\%=43.7\%[/tex]
N2O3 = 76.01 g/mol
[tex]\%N=\frac{2*14.01}{76.01}*100\%=36.9\%[/tex]
NH4Cl = 53.49 g/mol
[tex]\%N=\frac{1*14.01}{53.49}*100\%=26.2\%[/tex]
NH2OH = 33.03 g/mol
[tex]\%N=\frac{1*14.01}{33.03}*100\%=42.4\%[/tex]
In such a way, the compound with the highest percentage of nitrogen by mass is NH4NO2.
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